Question

solve the following pair of linear equation by the elimination method and substitution method. (2) 3x+4y=10 and 2x-2y=2​

Answer 1

Answer:

3x+4y=10

or x=(10-4y)/3...........eq 1

putting the value in eq2

20-8y/3-2y=2

20-14y=6

14=14y

y=1

thus x= 2

by elimination

3x+4y=10..........eq1

2x-2y=2....multiplying both sides by2

4x-4y=8............eq2

adding eq1 and eq2

7x=18

x=2.5

y=1.5

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