solve the following pair of linear equation by the substitution method...
√2x + √3y = 0
√3x - √8y = 0
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We have,
- √2x + √3y = 0
- √3x - √8y = 0
From Equation (1), We deduce:
⇒ √2x = -√3y
⇒ x = -√3y / √2
Plugging in equation (2),
⇒ √3(-√3y/√2) - √8y = 0
⇒ -3y/√2 - 2√2y = 0
Taking y in common,
⇒ y ( -3/√2 - 2√2) = 0
⇒ y = 0
Then,
⇒ x = -√3 × 0 / √2
⇒ x = 0
Hence,
The required value of x and y:
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For solving the above, you can also try using the other ways of solving like:
- Graphical method
- Elimination method
- Cross multiplication method.
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