Solve the following pair of linear equation by the substitution method 1) 0.2x+0.3y=1.3 , 0.4x+0.5y=2.3
Answers
Answer:
Step-by-step explanation:
Given :-
0.2x + 0.3y = 1.3
0.4x + 0.5y =2.3
Solution :-
0.2x + 0.3y = 1.3 ... (i)
0.4x + 0.5y = 2.3 ... (ii)
0.2x + 0.3y = 1.3
Solving equation (i), we get
0.2x = 1.3 - 0.3y
Dividing by 0.2, we get
x = 1.3/0.2 - 0.3/0.2
x = 6.5 - 1.5 y ... (iii)
Putting the value in equation (ii), we get
0.4x + 0.5y = 2.3
⇒ (6.5 - 1.5y) × 0.4x + 0.5y = 2.3
⇒ 2.6 - 0.6y + 0.5y = 2.3
⇒ –0.1y = 2.3 - 2.6
⇒ y = - 0.3/-0.1
⇒ y = 3
Putting this value in equation (iii) we get
⇒ x = 6.5 - 1.5 y
⇒ x = 6.5 - 1.5(3)
⇒ x = 6.5 - 4.5
⇒ x = 2
Hence, x = 2 and y = 3.
Answer:
0.2x+0.3y=1.3...
(i) 0.2x + 0.3y = 1.3
Solving equation (i), we get
0.2x = 1.3 - 0.3y
Dividing by 0.2, we get
x = 1.3/0.2 - 0.3/0.2; x=6.5-1.5y...
Step-by-step explanation:
0.4x+0.5y=2.3
0.4x + 0.5y = 2.3
=>(6.5-1.5y)0.4x+0.5y=2.3
=>(2.6-0.6y+0.5y=2.3)
=> -0.1y=2.3-2.6
=> y=-0.3/-0.1
x=3
Putting this value in equation
(iii) we ge x=6.5-1.5y
⇒ x = 6.5 - 1.5(3)