solve the following pair of linear equation for x and y by elimination substitution cross multiplication and graphical method 1.3x=y+5 5x-y=1
2. x+2y=2 x-3y=7
3. 3x-y=7 2x+5y+1=0
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Given equations are,
2x − 3y = 7 ..(1)
and 5x + y = 9 ..(2)
Multiply equation (2) by 3,
we get 15x + 3y = 27 ..(3)
Add equations (1) and (3),
17x = 34 ⇒ x = 2
Put this value in equation (2),
we get 5(2) + y = 9 ⇒ 10 + y = 9 ⇒ y = −1
Therefore, the solution is x = 2,y = 1
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