solve the following pair of linear equation graphically x+2y=1 x-2y=-7
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x + 2y = 1 ......................(1)
x - 2y = -7 .......................(2)
From eq. (1) we get,
Let take x = 1 and y = 0
Substitute the value of x in eq.
= x + 2y = 1
= x = 1 - 2y
= (1) = 1 - 2 (0)
= 1 = 1 - 0
= 1 = 1
Hence the first coordinate will be (1,0)
Let x = 3 and y = -1
Put the value we get,
= x = 2y = 1
= x = 1 - 2y
= (3) = 1 - 2 (-1)
= 3 = 1 + 2
= 3 = 3
So, the next coordinate is (3, -1)
From eq. 2 we get,
Let take the x = 1 and y= 4
Put the value in eq. we get,
= x - 2y = -7
= x = -7 + 2y
= (1) = -7 + 2 (4)
= 1 = -7 + 8
= 1= 1
The coordinate is (1,4)
Let's take another value of x = 3 and y = 5
Put value,
= x - 2y = -7
= x = -7 + 2y
= (3) = -7 + 2 (5)
= 3 = -7 + 10
= 3 = 3
Hence the coordinate is (3, 5)
X/Y = 1/0, 3/1 .................... From first equation
X/Y = 1/4, 3/5 .................... From second equation
Hope this answer will help you ................
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x - 2y = -7 .......................(2)
From eq. (1) we get,
Let take x = 1 and y = 0
Substitute the value of x in eq.
= x + 2y = 1
= x = 1 - 2y
= (1) = 1 - 2 (0)
= 1 = 1 - 0
= 1 = 1
Hence the first coordinate will be (1,0)
Let x = 3 and y = -1
Put the value we get,
= x = 2y = 1
= x = 1 - 2y
= (3) = 1 - 2 (-1)
= 3 = 1 + 2
= 3 = 3
So, the next coordinate is (3, -1)
From eq. 2 we get,
Let take the x = 1 and y= 4
Put the value in eq. we get,
= x - 2y = -7
= x = -7 + 2y
= (1) = -7 + 2 (4)
= 1 = -7 + 8
= 1= 1
The coordinate is (1,4)
Let's take another value of x = 3 and y = 5
Put value,
= x - 2y = -7
= x = -7 + 2y
= (3) = -7 + 2 (5)
= 3 = -7 + 10
= 3 = 3
Hence the coordinate is (3, 5)
X/Y = 1/0, 3/1 .................... From first equation
X/Y = 1/4, 3/5 .................... From second equation
Hope this answer will help you ................
If so please mark it as brainliest.....
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