Solve the following pair of linear equations
7x + 3y = 27
2x + 5y = 16
Answers
Answered by
0
Answer:
multiply the first equation by 5 and the second by 3
and then subtract so you'll get the value of x then find the value of y by substituting the value of x in one of the equa8
Answered by
1
Answer:
y=2
x=3
Step-by-step explanation:
7x=27-3y
x=27-3y/7
2x+5y=16
2x=16-5y
2x=2[27-3y/7]
16-5y=2[27-3y/7]
16-5y/2=27-3y/7
cross multiply
[16-5y]7=[27-3y]2
112-35y=54-6y
112-54=35y-6y
58=29y
y=58/29
y=2
7x+3[2]=27
7x=27-6
7x=21
x=3
y=2
x=3
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