Question

Solve the following pair of linear equations by multiplication method:-
1) 11x+15y+23=0
7x-2y-20=0

Answer 1

Answer:

In Elimination Method .

11x+15y+23=0

11x+15y= -23. (equ.1st)

7x-2y-20=0

7x-2y=20. (equ.2nd)

11x+15y=-23

7x-2y = 20

multiply by (2) in equ. 1st &( 15) in equ. 2nd we get.

22x+30y= -46. ( equ. 3rd)

105x-30y= 300. (equ. 4th)

_____________

127x=254

X=254/127

X = 2.

put the value of X in equ. 2nd

7x-2y=20

7(2)-2y =20. (X=2)

14-2y =20

-2y=20-14

-2y= 6

y= 6/-2

y=-3.

Your answer => X = 2 , Y= -3.

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Answer 2

Answer:

x/-300-(-46) =-y/-220-161. =1/-220-105

x/-254. =1/_127

x=254/305=

y= -361/305