solve the following pair of linear equations by any suitable method 5 x + 4 Y - 4 is equal to zero x minus 12 minus 20 is equal to zero
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The values of x and y to the given linear equations are x=32 and y=-39
The solution is (32,-39)
Step-by-step explanation:
Given equations are 5x+4y-4=0 _____ (1) and x-12-20=0
x-12-20=0
x-32=0
Therefore x=32
Solving the given equations by substitution method
Substitute x=32 in equation (1) we have
5(32)+4y-4=0
160+4y-4=0
156+4y=0
156+4y-156=0-156
4y=-156
Therefore y=-39
The values of x and y are x=32 and y=-39
The solution is (32,-39)
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