solve the following pair of linear equations by cross-multiplication method: 3x+2y=13. 7x-5y=11
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0
3x+2y=13,7x-5y=11
x=3, y=2.......…
Answered by
0
Answer:
The given system of equations is 3x+5y−25=0
7x+6y−30=0
Now, writing the coefficients for cross multiplication, we get
−150+150
x
=
−175+90
y
=
18−35
1
. i.e.,
0
x
=
−85
y
=
−17
1
.
Thus, we have x = 0, y = 5. Hence, the solution is (0, 5).
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