Question

Solve the following pair of linear equations by elimination method.
x + 8y = 21
6x + 7y = 3
X =
y=​

Answer 1

Answer:

Hello....

By elimination method

X+8y = 21...... (1)

6x +7y = 3...... (2)

By (1) and (2)

6×(1).... 6x+48y = 126

1× (2).... 6x+7y = 3

(-) (-) (-)

.....................................

41 y = 123

Y = 3...

Substituting y in (1)

X+8(3)= 21

X+24=21

X = 21-24

X = -3....

:. X = -3, y=3...

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Answer 2

Answer:

$x + 8y = 21...........(1) \\ 6x + 7y = 3............(2) \\ \\ from \: equation \: (1) \: and \: (2) \\ by \: elemination \: method \\( x + 8y = 21) \times 6.....(1) \\ \\ now \\ 6x + 48y = 126 \\ \frac{6x + 7y = \: \: \: \: \: \: 3}{41y = 123 } \\ \: \: \: \: \: \: \: \: \: \: y = 3.......(3) \\ putting \: the \: value \: of \: y \: in \: equation \: (1) \\ x + 8y = 21 \\ x + 24 = 21 \\ x = - 3 \\ \\ therefore \: value \: of \\ x = - 3 \\ y = 3$

Step-by-step explanation:

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