Question

Solve the following pair of linear equations by
elimination method:
2x + 3y = 13
4x – y = 12

Answer 1

The answer is given below........

Answer 2

$Given \:pair \:of \:linear \: equations : \\2x + 3y = 13 \: --(1) \\and \: 4x - y = 12 \: --(2)$

/* Multiplying equation (2) by 3 and add equation (1) , we get */

$3(4x-y) + 2x + 3y = 3\times 12 + 13$

$\implies 12x - 3y + 2x + 3y = 36 + 13$

$\implies 12x + 2x = 36 + 13$

$\implies 14x = 49$

$\implies x = \frac{49}{14}$

$\implies x = \frac{7}{2} \: --(3)$

$Put \: x = \frac{7}{2} \: in \: equation \:(1) , \\we \:get$

$2 \times \frac{7}{2} + 3y = 13$

$\implies 7 + 3y = 13$

$\implies 3y = 13 - 7$

$\implies 3y = 6$

$\implies y = \frac{6}{3}$

$\implies y = 2$

Therefore.,

$\red { x } \green {= \frac{7}{2}}$

$\red { y} \green { = 2}$

•••♪