Solve the following pair of linear equations by elimination method 3x-7y+10=0 y-2x-3=0
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Answer:
3x-7y+10=0......(1).
y-2x-3=0......(2).
From equation (2) we get.
y=2x+3.
By substituting y=2x+3 in equation (1) we get.
3x-7(2x+3)+10=0.
3x-14x-21+10=0.
3x-14x=+21-10.
-11x=11.
x=11/-11.
x=-1.
By putting x=-1 in y=2x+3 we qet.
y=2(-1)+3.
y=-2+3.
y=1.
Therefore x=-1 & y=1 by elimination method.
I think this is your answer.
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