solve the following pair of linear equations by elimination method and substitution method x+y=15 and x-y=1
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Step-by-step explanation:
By elimination method
x + y = 15----(1) , x - y = 1------(2)
using equation( 1)&(2)
x + y = 15----(1)
x - y = 1------(2)
————————
2x = 16
x = 16/2
x = 8
using equation x = 8 in (1)
8 + y = 15
y = 15 - 8
y = 7
By substitution method
x + y = 15 , x - y = 1------(2)
x + y = 15----(1) , x = 1 + y------(3)
using equation( 1)in(3)
1 + y + y = 15
2y = 15 - 1
y = 14/2
y = 7
using equation y = 7 in (1)
x + 7 = 15
x = 15 - 7
x = 8
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