Question

Solve the following pair of linear
equations by elimintion method
3x+2y-2=0; 2x+ 5y +6=0​

Answer 1

Step-by-step explanation:

$\sf 3x + 2y - 2 = 0$

$\sf 2x + 5y + 6 = 0$

$\text{Writing the equations in their standard form,}$

3x + 2y - 2 = 0

3x + 2y = 2

2x + 5y + 6 = 0

2x + 5y = - 6

$\sf 3x + 2y = 2$

$\sf 2x + 5y = -6$

Let's eliminate x .

Multiplying the first eq. by 2 and 2nd eq. by 3 to make the coefficients of x same in both eq.

$\sf 2(3x+2y=2)$

$\sf 3(2x + 5y = -6)$

(Subtracting the equations will change the signs in each term)

$\sf \: 6x + 4y = 4$

(-) $\sf \underline{6x (-)+ 15y = (-)-18}$

-11y = 22

$\boxed{\sf y = -2}$

$\sf 3x + 2y=2$

$\sf 3x + 2(-2) = 2$

$\sf \implies 3x-4=2$

$\sf \implies 3x = 4+2$

$\sf \implies 3x = 6$

$\boxed{ \sf x=2}$

Hope it helps.