Question

Solve the following pair of linear equations by reducing them to a pair of linear equations
$\frac{1}{2x} + \frac{1}{3y} = 2 \\ \frac{1}{3x} + \frac{1}{2y} = \frac{13}{6}$
$\frac{4}{x} + 3y = 14 \\ \frac{3}{x} - 4y = 23$
$\frac{10}{x + y} + \frac{2}{x - y} = 15 \\ \frac{15}{x + y} - \frac{5}{x - y} = - 2$
$\frac{2}{ \sqrt{x} } + \frac{3}{ \sqrt{y} } = 2 \\ \frac{4}{ \sqrt{x } } - \frac{9}{ \sqrt{y} } = - 1$
$\frac{5}{x - 1} + \frac{1}{y - 2} = 2 \\ \\ \frac{6}{x - 1} - \frac{3}{y - 2}$
$6x + 3y = 6xy \\ 2x + 4y = 5xy$
$\frac{1}{3x + y} + \frac{1}{3x - y} = \frac{3}{4} \\ \frac{1}{2(3x + y)} - \frac{1}{2(3x - y)} = \frac{ - 1}{8}$

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Answer 1

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Answer 2

Answer:

x 1

y 1

hope so It is helpful for u