solve the following pair of linear equations by substituting method, 2x-y=-10 , - 6x+3y=30
Answers
Answered by
6
2(-10)-y=0
= -20-y=0
= y=20
6(-10)+3y=30
= -60+3y=30
= 3y=30+60
= y=90/3
= y=30
= -20-y=0
= y=20
6(-10)+3y=30
= -60+3y=30
= 3y=30+60
= y=90/3
= y=30
Answered by
21
hope its correct....
its absolutely correct u caan verify this....
its absolutely correct u caan verify this....
Attachments:
ajat:
thanks
Similar questions