Question

Solve the following pair of linear equations by substitution method.
2x + 3y = 13, 4x - y = – 9.​

Answer 1

Answer:

x=5

y=-1

Step-by-step explanation:

$2x + 3y = 13 - - - - - eq1 \\ 4x - y = - 9 - - - - - eq2 \\ eq1 = x = \frac{13 - 3y}{2} - - - eq3 \\ using \: eq3 \: in \: eq2\\ 4( \frac{13 - 3y}{2} ) - y = - 9 \\ \frac{52 - 12y - 2y}{2} = - 9 \\ 52 - 12y - 2y = - 18 \\ - 14y = - 70 \\ y = 5 \\ x = \frac{13 - 3(5)}{2} \\ \frac{13 - 15}{2} \\ x = \frac{ - 2}{2} \\ x = - 1$

Answer 2

✨Question .

Solve the linear equation by substitution method.

2x+3y= 13

4x-y=-9

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✨Method used ..

Substitution Method .

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✨ Solution..

$2x + 3y = 13 .........(1) \\ \\ 4x - y = - 9............(2) \\ \\ 2x = > 13 - 3y \\ \\ x = > \frac{13 - 3y}{2} .............(3) \\ \\ \\ put \: the \: value \: of \: x \: in \: eq(2) \\ \\ 4( \frac{13 - 3y}{2}) - y = - 9 \\ \\ 2(13 - 3y) - y = - 9 \\ \\ 26 - 6y - y = - 9 \\ \\ 26 - 7y = - 9 \\ \\ - 7y = - 9 - 26 \\ \\ - 7y = - 35 \\ \\ y = \frac{35}{7 } \\ \\ \boxed{y = > 5} \\ \\ put \: the \: value \: of \: y \: in \: eq \: (1) \\ \\ 2x + 3(5) = 13 \\ \\ 2x + 15 = 13 \\ \\ 2x = 13 - 15 \\ \\ 2x = - 2 \\ \\ x = \frac{ - 2}{2} \\ \\ \boxed{x = > - 1}$

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✨Verification...

Put the values of x and y in equation (1)

$2x + 3y = 13 \\ \\ 2( - 1) + 3(5) = 13 \\ \\ - 2 + 15 = 13 \\ \\ 13 = 13 \\ \\ hence \: verified \: \: \: ........$

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Hope it's helps you

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Thanks☺️✨✨✨