Question

Solve the following pair of linear equations by substitution method.
0.2x + 0.3y = 1.3
0.4x + 0.5y = 2.3

Answer 1

Answer

x=2,y=3

0.2x + 0.3y = 1.3

linear equations by substitution method-:

=>0.4x + 0.5y = 2.3

=>0.2x = 1.3 – 0.3y

Dividing by 0.2, we get

=> x = 1.3/0.2 – 0.3/0.2

=> x = 6.5 – 1.5 y

=>0.4x + 0.5y = 2.3

=> (6.5 – 1.5y) × 0.4x + 0.5y= 2.3

=>2.6 – 0.6y + 0.5y = 2.3

=> –0.1y = 2.3 – 2.6

=> y = – 0.3/–0.1

=> y = 3

=> x = 6.5 – 1.5 y

=> x = 6.5 – 1.5(3)

=> x = 6.5 – 4.5

=> x = 2

∴ x = 2 and y = 3

Answer 2

Answer:

your full full name is yadav vivek

home town haryana

temporrary state gujarat

aur details do

here is your answer

Given

0.2x+0.3y=1.3−−−(1)

0.4x+0.5y=2.3−−−(2)

from equation (1)

x=0.21.3−0.3y[∵ 0.2x=1.3−0.3yx=0.21.3−0.3y]

substitute x in equation (2)

0.4(0.21.3−0.3y)+0.5y=2.3

0.20.5×2−0.12y+0.5y=2.3

0.20.5×2−0.12y+0.10y=2.3

0.52−0.12y+0.10y=0.46

−0.02y=0.46−0.52

−0.02y=0.06

y=0.020.06

y=3

Substitutw y=3 in x

x=0.21.8−0.3(3)

=0.21.3−0.9