solve the following pair of linear equations by substitution method y-5=0 3x+4y-20=0
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put y=5in equation and find c
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Answer:
The value of x = 0
The value of y = 5
Step-by-step explanation:
Given,
y -5 = 0 and 3x+4y - 20 = 0
To find,
The solutions of this pair of linear equations by substitution method
Solution:
y -5 = 0 ---------------(1)
3x+4y - 20 = 0 ---------(2)
From equation (1) we have, y = 5
Substitute the value of 'y' in equation (2) we get
3x +4×5 -20 = 0
3x + 20 -20 = 0
3x = 0
x = 0
The value of x = 0
The value of y = 5
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