Question

Solve the following pair of linear equations by substitution method.

$4x - 3y = 8 \\ 6x - y = \frac{29}{3}$
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Answer 1

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Answer 2

Answer:

The solution is as follows:-

$4x - 3y = 8.......(1)$

$6x - y = \frac{29}{3} ......(2)$

$on \: multiplying \: (2) \: by \: 3 \: we \: get.$

$18x - 3y = 29......(3)$

On subtracting (3) from (1), we get:

$- 14x = - 21$

$x = \frac{21}{14} = \frac{3}{2}$

$now \: substituiting \: the \: value \: of \: x = \frac{3}{2} in \: (1) \\ \: we \: get$

$4 \times \frac{3}{2} - 3y = 8$

$=> 6 - 3y = 8$

$3y = 6 - 8$

$3y = - 2$

$y = \frac{ - 2}{3}$

$hence \: the \: solution \: x = \frac{3}{2} \: and \: y = \frac{ - 2}{3} .$

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