Question

Solve the following pair of linear equations by substitution method x +3y =10 and 4x+5y=19

Answer 1

Step-by-step explanation:

x+3y=10

4x+5y=19

multiply 1 equation by 4

4x+12y=40. __________" (3)

4x+5y=19. _________''_(4)

subtract 3 from 4

(4x-4x)+(12y-5y)=(40-19)

7x=21

X=3

put value of X in in 3

you will get your answer

Answer 2

Answer:

x +3y =10   1

4x+5y=19   2

1*4

4x +12y =40 (1-2

4x+5y=19  

7y=21

y=3

x=1

Step-by-step explanation: