Question

Solve the following pair of linear
equations by Substitution method
3ax+2by-4-11=0; 2ax-3by+I0=0​

Answer 1

Answer:

3ax+2by-4-11=0

3ax+2by-15=0 1st eq

2ax-3by+10=0 2nd eq

both multiply eq 1st by 2 and eq 2nd by 3

6ax+4by=30

6ax-9by=-30

(-)   (+)       (+)

      13by=60

       by=60/13

        by=60/13

3ax+2(60/13)=15

3ax+120/13=15

3ax+120=195

3ax=195-120

3ax=75

ax=25

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Step-by-step explanation: