Solve the following pair of linear equations by substitution method: x-y=4
x/4+ y/3= 8
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Answer:
x - y = 4. eq. 1
x = 4 + y
put this value in equation 2
4 + y /4 + y/3 = 8
take LCM
12 + 3y +4y/ 12 = 8
12 + 7y = 8*12
7y = 8*12 -12
7y = 12(8-1)
7y = 12*7
y = 12
the value of y is 12
x = 12+4
x = 16
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