Question

Solve the following pair of linear equations by substitution method..
i) 3x +7y =37,5x+6y= 39

Answer 1

The value of x is 3 and
the value of y is 4

HOPE it helps to you !!!!!

Answer 2

Answer:

Required solution is $x = 3 \: and \: y = 4$

Step-by-step explanation:

Given two equations,

$3x + 7y = 37.....(1)$ and $5x + 6y = 39.....(2)$

From equation (1),

$3x + 7y = 37 \\ 3x = 37 - 7y \\ x = \frac{37 - 7y}{3} ....(3)$

We are putting value of x in equation (2),

$5 \times ( \frac{37 - 7y}{3} ) + 6y = 39 \\ \frac{185 - 35y}{3} + 6y = 39 \\ \frac{185 - 35y + 18y}{3} = 39 \\ \frac{185 - 17y}{3} = 39 \\ 185 - 17y = 117 \\ 17y = 185 - 117 \\ 17y = 68 \\ y = \frac{68}{17} \\ y = 4$

Putting value of y is equation (3),

$x = \frac{37 - 7 \times 4}{3} \\ x = \frac{37 - 28}{3} \\ x = \frac{9}{3} \\ x = 3$

Required value of x is 3 and value of y is 4.

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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