Question

solve the following pair of linear equations by substitution method 2X-3y + 15 = 0 ; 3X- 5 =0

Answer 1

I dont know the first one but the second is 5/3

Answer 2

3x-5=0 now, x= 3x=5 , x=5/3 then ,Now put the value 2*5/3-3y+15 =0 Then, 10/3-3y = - 15. -3y=-15-10/3 . -3y=-55/3 y= 55/9