Math, asked by Ayswariya03, 1 year ago

solve the following pair of linear equations by substitution method 2X-3y + 15 = 0 ; 3X- 5 =0

Answers

Answered by nyatharavindhra915

6

I dont know the first one but the second is 5/3

Answered by MuktiNarayan

16

3x-5=0 now, x= 3x=5 , x=5/3 then ,Now put the value 2*5/3-3y+15 =0 Then, 10/3-3y = - 15. -3y=-15-10/3 . -3y=-55/3 y= 55/9

Ayswariya03: I am thinking so y = - 55/9

Ayswariya03: sorry I understood

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