Question

Solve the following pair of linear equations by the
elimination method:
0.3x - 0.8y = -1.1
0.5x -0.7y =0.7

Answer 1

Answer:

Step-by-step explanation:

By multiplying eq1 with 0.5 and eq2 with 0.3

We get,

0.15x-0.40y+0.55=0 -----1

0.15x- 0.21y-0.21=0--------2

On eliminating x we get

- 0.19y+0.76=0

Therefore y = 0.76÷0.19

We get y =4

Substitute y=4 in any equation

We get x=7

Answer 2

Step-by-step explanation:

We Have :-

$0.3x - 0.8y = - 1.1 \\ \\ \\ 0.5x - 0.7y = 0.7$

To Find :-

$value \: of \: x \: and \: y$

Method Used :-

$elimination \: method$

Solution :-

$0.3x - 0.8y = - 1.1 - - - (1)\\ \\ \\ multiply \: (1) \: with \: 5 \\ \\ \\ 1.5x - 4y = - 5.5 - - - (2) \\ \\ \\ \\ 0.5x - 0.7y = 0.7 - - - (3) \\ \\ \\ multiply \: (3) \: with \: 3 \\ \\ \\ 1.5x - 2.1y = 2.1 - - - (4) \\ \\ \\ subtracting \: (4) \: from \: (2) \\ \\ \\ \: \: \: \: \: 1.5x - 4y = - 5.5 \\ \\ \\ - (1.5x - 2.1y = 2.1) \\ \\ \\ - 1.9y = - 7.6 \\ \\ \\ 19y = 76 \\ \\ \\ y = 4 \\ \\ \\ putting \: this \: value \: in \: (1) \\ \\ \\ 0.3x - 0.8(4) = - 1.1 \\ \\ \\ 0.3x - 3.2 = - 1.1 \\ \\ \\ 0.3x = - 1.1 + 3.2 \\ \\ \\ 0.3x = 2.1 \\ \\ \\ 3x = 21 \\ \\ \\ x = 7$