Solve the following pair of linear equations by the substitution method.
(i) x + y = 14
x – y = 4
(ii) 3x – y = 3
9x – 3y = 9
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(i) Given:
x + y = 14 and x - y = 4 are the two equations.
From 1st equation, we get:
- x = 14 - y
Now, put the value of x in second equation to get,
(14 - y) - y = 4
➠ 14 - 2y = 4
➠ 2y = 10
➠ Or y = 5
By the value of y, we can now find the exact value of x;
∵ x = 14 - y
∴ x = 14 - 5
Or x = 9
- Hence, x = 9 and y = 5.
(ii) Given:
3x - y = 3 and 9x - 3y = 9 are the two equations.
From 1st equation, we get,
- x = (3 + y)/3
Now, substitute the value of x in the given second equation to get,
9(3 + y)/3 - 3y = 9
➠ 3(3 + y) - 3y = 9
➠ 9 + 3y - 3y = 9
➠ 9 = 9
- Therefore, y has infinite values and since, x = (3 + y)/3, so x also has infinite values.
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Answer:
x=14-y
14-y-y=4
-2y=-10
y=10 ANS.
x=4 ANS.
ii) 3x=3+y
x=3+y/3
9 ×3+y/3 - 3y=9
9+3y-3y=9
0
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