Question

Solve the following pair of linear equations by the substitution , elimination and cross multiplication methods:. 9x+5y=3 and 3x+2y=4

Answer 1

Answer:-

$9x + 5y = 3 - - - - - 1 \\ 3x + 2y = 4 - - - - - 2 \times 3 \\ solve \: equation \: 1 \: and \: 2 \\ \ 9x + 5y = 3 \\ 9x + 6y = 12 \\ - - - - - - - - \\ \: \: \: \: \: \: \: \: \: - y = - 9 \\ y = 9(substitute \: in \: eq - 1) \\ 9x + 5y = 3 \\ 9x + 45 = 3 \\ 9x = - 42 \\ x = \frac{ - 42}{9} = \frac{ - 14}{3}$