Math, asked by admoh468, 8 months ago

Solve the following pair of linear equations by the substitution method. 1. x+y =14 x-y = 4 2. 3x-y=3 9x-3y=9 3. 2x+3y+5=0 3x-2y-12=0 4. y-4x=1 6x-5y=9 plz write the answer for 3 & 4 fast

Answers

Answered by shanukumar16372
2

Answer:

1 part

x+y=14 equation 1

x-y =4 equation 2

From equation 1

x+y=14

x=14-y equation 3

putting the value of x in equation 2

x-y=4

14-y-y=4

-2y=4-14

-2y= -10

y=-10/2

y=5

From equation 3

x=14-5

x=9

2part

3x-y=3 equation 1

9x-3y= equation 2

From equation 1

3x-y=3

3x=3+y

x=3+y/3 equation 3

9[3+y/3]-3y=9

9+3y-3y=9

9=9

It has many solution.

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