Math, asked by simranpande, 9 months ago

solve the following pair of linear equations by the substitution method- 3x+6y=3900,x+2y=1300

Answers

Answered by 004420
2

Step-by-step explanation:

Take any 1 equation and find the x or y value as follows

x+2y=1300

x=1300-2y

here we the x value

substitute the x value in another equation

-3*1300-2y+6y=3900

-3900+6y+6y=3900

-3900+12y=3900

-3900-3900+12y=0

-7800+12y=0

now find the y value

y=650

substitute in any of the one equation

x+2y=1300

x-2*650=1300

x-1300=1300

x=2600

Therefore x=2600 and y=650

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