Solve the following pair of linear equations by the elimination method
a) x+y=5 and 2x -3y =4
b) 3x+4y =10 and 2x -2y 2
d) 1 and -3
c) 3x-5y-4 =0 and 9x= 2y +7
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Here,given
a=1
d=4−1=3
and,s
n
=287
Now,
s
n
=
2
n
(2a+(n−1)d)
⇒287=
2
n
(2×1+(n−1)3)
⇒287=
2
n
(2+3n−3)
⇒574=n(3n−1)
⇒574=3n
2
−n
⇒3n
2
−n−574=0
onsolvingthequadraticequaton
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