Question

Solve the following pair of linear equations by the elimination method. x + y = 5, 2x - 3y = 4​

Answer 1

EXPLANATION.

equation are =

=> x + y = 5 ......(1)

=> 2x - 3y = 4 ......(2)

From equation (1) and (2)

we get,

=> x = 5 - y ..........(3)

put the value of equation (3) in equation (2)

we get,

=> 2 ( 5 - y) - 3y = 4

=> 10 - 2y - 3y = 4

=> 10 - 5y = 4

=> -5y = -6

=> y = 6/5

put the value of y = 6/5 in equation (3)

=> x = 5 - 6/5

=> x = 25 - 6 / 5

=> x = 19/5

Therefore,

=> x = 19/5 and y = 6/5

Answer 2

Answer:

✡ Given ✡

$\mapsto$ x + y = 5

$\mapsto$ 2x - 3y = 4

✡ To Find ✡

$\leadsto$ Value of x and y.

✡ Method Used ✡

$\mapsto$ Elimination Method.

✡ Solution ✡

$\mapsto$ x + y = 5 ..... Equation no (1)

$\mapsto$ 2x - 3y = 4 ..... Equation no (2)

➡ Multiplying (1) with 3 and adding with (2) we get,

$\leadsto$ 3x + 3y = 15

$\leadsto$ 2x - 3y = 4

$\implies$ 5x = 19

$\implies$ x = $\dfrac{19}{5}$

Again,

Putting the value of x = $\dfrac{19}{5}$ we get,

$\implies$ y = 5 - x

$\implies$ y = $\dfrac{5 - 19}{5}$

$\implies$ y = $\dfrac{25 - 19}{5}$

$\implies$ y = $\dfrac{6}{5}$

$\therefore$ The value of x = $\dfrac{19}{5}$ and y = $\dfrac{6}{5}$

Step-by-step explanation:

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