Question

Solve the following pair of linear equations by the substitution method. 1) 2x+y=2; 2y-x=4

Answer 1

Answer:

x=0y=2

Step-by-step explanation:

2x+y=2. equations.1

2y-x. =4. equations 2

by applying substitution method

from equations 1

y=2-2x. equations 3

put the value of equations 3ti equation 2

equation 2 will be now

2(2-2x)=4

4-4x=4

-4x=0

x=0

and therefore now put the value of x=0in equation 1

2(0)+y=2

y=2

Answer 2

Step-by-step explanation:

2x+y=2 ,2y-x=4

from eq I we get x =2-y/2 put the value in eq 2

2y-2-y/2=4

4y-(2-y)/2=4

4y-2+y/2=4

4y-2+y=8

5y-2=8

5y=10

y=2

put y=2in eq 1

2x+2=2

2x=2-2=0

2x=0

x=0