Solve the following pair of linear equations by the substitution method. 0 . 5 x + 0.2 y = 1.5 and 0. 4 x + 0 . 7 y = − 1 . 5 find x and y
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0
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ANSWER
7x+11y=0 ......(i)
3x−5y=0 ......(ii)
On multiplying equation (i) by 3 and equation (ii) by 7. we get,
21x+33y=0 ......(iii)
21x−35y=0 ......(iv)
On subtracting equation (iv) from equation (iii). we get,
21x+33y=0
−21x−+35y=−0
(33+35)y=0
⇒y=0
On substituting y=0 in equation (i). we get,
7x+11×0=0
⇒7
Answered by
1
Answer:
Step-by-step explanation:
if you have problem with decimal,then multiply both the equation by 10
5x+2y=15 and 4x+7y=-15
now 5x=15-2y or x=15-2y/5 or x=3-2y/5
in eq2 4(3-2y/5)+7y=-15
12-8y/5 +7y=15
(60-8y+35y)/5=15 lcm
-8y+35y+60=15*5
27y=75-60
y=15/27 =5/9 or 0.5
put value of y in eq
x=3-(2/5*5/9)
x=3-2/9 = 25/9 or 2.8
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