Question

Solve the following pair of linear equations by the substitution method x/3+0.5y=13/6,1.5x-5y/3+2=0​

Answer 1

Answer:

x=2 and y=3

Step-by-step explanation:

Let's solve your system by substitution.

x/3+0.5y=13/6;1.5x−5y/3+2=0

Rewrite equations:

1/3x+0.5y=13/6;1.5x+−5/3y+2=0

Step: Solve

1/3x+0.5y=13/6 for x:

1/3x+0.5y=13/6

1/3x+0.5y+−0.5y=13/6+−0.5y(Add -0.5y to both sides)

1/3x=−0.5y+13/6

1/3x/1/3=−0.5y+13/6/1/3

(Divide both sides by 1/3)

x=−1.5y+13/2

Step: Substitute−1.5y+13/2for x in 1.5x+−5/3y+2=0:

1.5x+−5/3y+2=0

1.5(−1.5y+13/2)+−5/3y+2=0

−3.916667y+11.75=0(Simplify both sides of the equation)

−3.916667y+11.75+−11.75=0+−11.75(Add -11.75 to both sides)

−3.916667y=−11.75

−3.916667y/−3.916667=−11.75/−3.916667

(Divide both sides by -3.916667)

y=3

Step: Substitute3for y in x=−1.5y+13/2:

x=−1.5y+13/2

x=(−1.5)(3)+13/2

x=2(Simplify both sides of the equation)

Answer:

x=2 and y=3

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