Solve the following pair of linear equations by the substitution method : s – t = 3
, s/3+t/2=6
Answers
Step-by-step explanation:
Given:-
s – t = 3 , s/3+t/2=6
To find:-
Solve the following pair of linear equations by the substitution method : s – t = 3 , s/3+t/2=6
Solution:-
Given paor of linear equations are
s – t = 3 -------(1)
=> s = 3 + t ------(2)
And the given equation is s/3+t/2=6 ----(3)
On Substituting the value of s in (3) then
=>[(3+t)/3] + (t/2) = 6
LCM of 3 and 2 is 6
=>[2(3+t)+3t]/6 = 6
=>(6+2t+3t)/6 = 6
=>(6+5t)/6 = 6
=>(6+5t)=6×6
=>6+5t = 36
=> 5t = 36-6
=>5t = 30
=>t = 30/5
=>t = 6
On Substituting the value of t in (2) then
s = 3+6
s = 9
Therefore, s=9 and t = 6
Answer:-
The solution for the given pair of linear equations in two variables is (s,t) = ( 9 , 6 )
Check:-
If s=9 and t = 6 then LHS of (1)
9-6 = 3
LHS = RHS
If s=9 and t = 6 then LHS of (2)
(9/3)+(6/2)
=>3+3
=>6
LHS = RHS is true for s=9 and t = 6
Used Method:-
- Substitution method
Answer:
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