Question

solve the following pair of linear equations by the substitution method: 3x + 4y = 0; x - 5y = 19​

Answer 1

Given Equation

⇒3x + 4y = 0                (i)

⇒x - 5y = 19                  (ii)

To Find

⇒Value of x and y By using Substitution Method

Now take

⇒x - 5y = 19          (i)

⇒x = 19 + 5y             (iii)

Now put the value of x on (i) eq

⇒3x + 4y = 0         (i)

⇒3(19 + 5y) + 4y = 0

⇒57 + 15y + 4y =

⇒19y = -57

⇒y = -57/19

⇒y = -3

Now Put the value of y on (iii) eq

⇒x = 19 + 5y             (iii)

⇒x = 19 + 5(-3)

⇒x = 19 - 15

⇒x = 4

Answer

⇒x = 4 and y = -3

Answer 2

Answer:

3x+4y =0 - equation 1

x-5y = 19 - equation 2

from equation 1

3x = -4y

x = -4y/3 - equation 3

substitute the value of x in equation in 2

-4y/3 -5y =19

(-4y-15y)/3 =19

-19y = 19 × 3

y = -3

substitute the value of y in equation 3

x = -4(-3)/3

x = 4

therefore

x = 4

y = -3

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