Question

solve the following pair of linear equations by the substitution method. 3x-y=3
9x-3y=9​

Answer 1

Answer:

3x−y=3 …………(1)

3x−y=3 …………(1)9x−3y=9 ………..(2)

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=9

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)3(3x−y)=3×

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)3(3x−y)=3×

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)3(3x−y)=3×3 ………. (2)

3x−y=3 …………(1)9x−3y=9 ………..(2)substitution method3x−y=3y=3x−3 [put in equation 2]9x−3(3x−3)=99x−9x+9=9∴ ∞ solutions because both lines same3x−y=3 ……..(1)3(3x−y)=3×3 ………. (2)1=2.

Answer 2

Answer:

3x−y=3 …………(1)

9x−3y=9 ………..(2)

Substitution method

3x−y=3

y=3x−3 [Put in equation 2]

9x−3(3x−3)=9

9x−9x+9=9

∴ ∞ solutions because both lines same

3x−y=3 ……..(1)



3(3x−y)=3×



3 ………. (2)

1=2.