Question

Solve the following pair of linear equations by the substitution method : 5x + 6y = 14, 3x – 2y = –14​

Answer 1

Answer:

$5x = 14 - 6y \\ x = \frac{14 - 6y}{5} \\ 3( \frac{14 - 6y}{5} ) - 2y = - 14\\ \frac{42 - 18y}{5} - 2y = - 14 \\ \frac{42 - 18y - 10y}{5} = - 14 \\ \frac{42 - 28y}{5} = - 14 \\ 42 - 28y = - 70 \\ 28y = 112 \\ y = \frac{112}{28} = 4 \\ put \: in \: 1 \\ \frac{14 - 6 \times 4}{5} = \frac{ - 10}{5} = - 2$