Question

Solve the following pair of linear equations by the substitution method: √3x+√2y=0 ; √2x-√3y =0​

Answer 1

Answer:

x=0;y=0

Step-by-step explanation:

√3x+√2y=0 ... (1)

√2x-√3y =0 ...(2)

x=√3y /√2

substituting the value of x fom eq(1)

√3(√3y /√2)+√2y=0

(3y/√2)+√2y=0

(3y+2y)/√2y=0

y(3+2)=0*√2y

y(5)=0

y=0/5

:.y=0 Ans)

substituting the value of y from eq(2)

√2x-√3y =0

√2x-√3*0=0

√2x-0=0

√2x=0

x=0/√2

:.x=0 Ans)