Math, asked by diapatel2405, 5 hours ago

Solve the following pair of linear equations by the subsitution method 2x+3y=10;3x-y=4​

Answers

Answered by sakshamdua06
0

Answer:

x = 2, y = 2

Step-by-step explanation:

2x+3y = 10 ---- (1)

3x-y = 4 ---- (2)

3x-y = 4

y = 3x-4

Substituting y in (1)

2x+3(3x-4) = 10

2x + 9x - 12 = 10

11x - 12 = 10

11x = 10+12

11x = 22

x = 2

Substituting x in y

y = 3x-4

y = 3(2) - 4

y = 6 - 4

y = 2

Answered by srinugudiya829
0

Answer:

2x+3y=10

2x=10-3y

x=10-3y/2

3x-y=4

3(10-3y/2)-y=4

30-9y-2y=8

30-11y=8

11y=22

y=22/11=2

2x+3y=10

2x+3(2)=10

2x=4

x=2

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