Solve the following pair of linear equations by the substitution method.
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3x - y = 3
3x = 3+y
x = 3 + y / 3
9x -3y =9
9 × 3+y /3 - 3y = 9
3 ×(3 + y) - 3y = 9
9+3y -3y = 9
9 = 9
This gives us that,
these equations cannot be solved
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3x-y=3--------(1)
9x-3y=9-------(2)
multiplying equation 1 by 3 we get,
9x-3y=9--------(3)
9x+3y=9
adding equation 3and 2 we get,
18x. = 18
x=1
substituting x=1 in 2 we get
9x-3y=9
9(1)-3y=9
y=0
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