Math, asked by Clink, 1 year ago

Solve the following pair of linear equations by the substitution method.

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Answers

Answered by Maxcaulfield
7

3x - y = 3

3x = 3+y

x = 3 + y / 3

9x -3y =9

9 × 3+y /3 - 3y = 9

3 ×(3 + y) - 3y = 9

9+3y -3y = 9

9 = 9

This gives us that,

these equations cannot be solved

(answer)

Please mark as brainliest


Clink: your from?
Maxcaulfield: 10th
Clink: i mean place?
Maxcaulfield: I am from Delhi but I live in dubai
Clink: well i am in 10th too but its only 3 days in tenth so still in habit of saying 9
Clink: dubai! cool!
Maxcaulfield: I m gonna finish 10th
Clink: cool
Maxcaulfield: 3 board exams left
Clink: ok
Answered by keval43
6

3x-y=3--------(1)

9x-3y=9-------(2)

multiplying equation 1 by 3 we get,

9x-3y=9--------(3)

9x+3y=9

adding equation 3and 2 we get,

18x. = 18

x=1

substituting x=1 in 2 we get

9x-3y=9

9(1)-3y=9

y=0


keval43: bhai mark karde brainliest MUJE
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