Question

solve the following pair of linear equations by the substitution method ​

Answer 1

4x + y – 6 = 0

⇒ y = 6 – 4x

Value of y put in eqn. (i)

3x + 2y – 7 = 0

⇒ 3x + 2(6 – 4x) – 7 = 0

⇒ 3x + 12 – 8x – 7 = 0

⇒ 5 – 5x = 0

⇒ 5x = 5

x = 1

Substitute the value of x in eq (ii) to get value of y,

4x + y – 6 = 0

⇒ 4(1) + y – 6 = 0

⇒ 4 + y – 6 = 0

⇒ y – 2 = 0

y = 2

Hence, values of x and y are 1 and 2 respectively..

Answer 2

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