solve the following pair of linear equations by the substitution method
Attachments:
Answers
Answered by
4
4x + y – 6 = 0
⇒ y = 6 – 4x
Value of y put in eqn. (i)
3x + 2y – 7 = 0
⇒ 3x + 2(6 – 4x) – 7 = 0
⇒ 3x + 12 – 8x – 7 = 0
⇒ 5 – 5x = 0
⇒ 5x = 5
x = 1
Substitute the value of x in eq (ii) to get value of y,
4x + y – 6 = 0
⇒ 4(1) + y – 6 = 0
⇒ 4 + y – 6 = 0
⇒ y – 2 = 0
y = 2
Hence, values of x and y are 1 and 2 respectively..
kedarhussen:
sorry bro ans are not available
Answered by
0
It helpful for you.
Make me brainlest
Attachments:
Similar questions