Question

solve the following pair of linear equations for x and y:
please solve it with steps

Answer 1

Given : x/a + y/b = a + b 

On cross-multiplication, we get

bx + ay = a^2b + b^2a ------------------- (1)


Given: x/a^2 + y/b^2 = 2  

On cross-multiplication, we get

b^2x + a^2y = 2a^2b^2   --------------------- (2)


On solving (1) * b & (2), we get


b^2x + aby = a^2b^2 + b^3a   ------------ (3)

b^2x + a^2y = 2a^2b^2      ------------------- (4)

---------------------------------------------

            aby - a^2y = -a^2b^2 + b^3a

           ay(b - a) = ab^2(-a + b)

           ay = ab^2

            y = b^2.



Substitute y = b^2 in (4), we get

b^2x + a^2y = 2a^2b^2

b^2x + a^2b^2 = 2a^2b^2

b^2(x + a^2) = 2a^2b^2

x + a^2 = 2a^2

x = 2a^2 - a^2

x = a^2



Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks