solve the following pair of linear equations graphically, x+3y=6 , 2x-3y=12
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x+3y=6 ------ (1)
2x-3y=12 -----(2)
(1)+(2)=x+3y+2x-3y=18
x+2x=18
x=18/3=6
subsitute the value of x in (1)
6+3y=6
3y=6-6
3y=0
y=0
2x-3y=12 -----(2)
(1)+(2)=x+3y+2x-3y=18
x+2x=18
x=18/3=6
subsitute the value of x in (1)
6+3y=6
3y=6-6
3y=0
y=0
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