Question

solve the following pair of linear equations in two variables(by graph).x+y=1,3x+3y=2​

Answer 1

x+y=1,3x+3y=2

Solve by Substitution

Let's solve your system by substitution.

x+y=1;3x+3y=2

Step: Solve$x+y=1$for x:

$x+y=1$

$x+y+−y=1+−y$(Add -y to both sides)

$x=−y+1$

Step: Substitute−y+1forxin3x+3y=2:

$3x+3y=2$

$3(−y+1)+3y=2$

$3=2$(Simplify both sides of the equation)

$3+−3=2+−3$(Add -3 to both sides)

$0=−1$

Answer:

No solutions.

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Answer 2

Let's solve your system by substitution.

$x+y=1;3x+3y=2$

$\huge\red{Solve}$

$x+y=1x+y=1 \: for \: x:$

$x+y=1x+y=1$

$x+y+−y=1+−yx+y+−y=1+−y (Add -y \: to \: both \: sides)$

$x=−y+1x=−y+1$

$\huge\red{Substitute}$

$−y+1 \: for \: x \: in3x+3y=2:$

$3x+3y=23x+3y=2$

$3(−y+1)+3y=23(−y+1)+3y=2$

$3=23=2 (Simplify \: both \: sides \: of \: the \: equation)$

$3+−3=2+−33+−3=2+−3 (Add -3 \: to \: both \: sides)$

$0=−10=−1$

$\huge\orange{Answer:}$

No solutions.