Question

Solve the following pair of linear equations:

!! Please give the answer with solution or the answer will be reported !!!
$\frac{3}{x + y} + \frac{4}{x - y} = 5$

$\frac{5}{x + y} + \frac{1}{3(x - y)} = 2$​

Answer 1

Answer:

5x^2-5y^2=7x-y is the answer of 1st equation.

6x^2-6y^2=6x-14y is the answer of 2nd equation.

Step-by-step explanation:

3/x+y+4/x-y=5

3(x-y)+4(x+y)/(x+y)(x-y)=5

3x-3y+4x+4y/x^2-xy+xy-y^2=5

7x+y/x^2-y^2=5

5(x^2-y^2)=7x+y

5x^2-5y^2=7x+y

5/x+y+1/3(x-y)=2

5/x+y+1/3x-3y=2

5(3x-3y)+x+y/(x+y)(3x-3y)=2

15x-15y+x+y/3x^2-3xy+3xy-3y^2=2

16x-14y/3x^2-3y^2=2

2(3x^2-3y^2)=16x-14y

6x^2-6y^2=6x-14y

may be it's help you..

have a good day...