Question

Solve the following pair of linear equations :
$(2 \div \sqrt{x}) + (3 \div \sqrt{y} ) = 2$
and
$4 \div \sqrt{x} ) -( 9 \div \sqrt{y}) = 1$
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Answer 1

2/x^-2=2x^-2(rationalisation)
3/y^-2=3y^-2(———-“———)
Similarly,
4x^-2&9y^-2
So,
2x^-2 + 3y^-2 = 2——-(1)
And
4x^-2 - 9y^-2 = 1——-(2)
Multiplying 3 on both sides in eq. 1 we get
6x^-2 + 9y^-2 = 6——-(3)
Adding (1) & (3) we get,
6x^-2 + 9y^-2 = 6
+4x^-2 - 9y^-2 =+ 1
Therefore
10x^-2 = 7,
x = (7/10)^2,
x = 49/100,
x = 0.49.

Answer 2

Answer:

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Step-by-step explanation:

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