Solve the following pair of linear equations using substitution method:- 2 + 3 + 5 = 0 ; 5 − 3 + 9 = 0
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Answer:
(i) x+y=14⇒y=14−x
Substituting this value in the second equation, we get
x−(14−x)=4
2x=18⇒x=9
Substituting this value of x in the first equation, we get
9+y=14⇒y=5
(ii) s−t=3⇒s=t+3
Substituting in 2nd equation
3t+3+2t=6
62t+6+3t=6
5t+6=36⇒t=6
Substituting value of t in 1st equation
s=t+3=9
(iii) ∵a2a1=b2b1=c2c1
Hence all the points lying on the line y=3x−3 like x=2,y=3; are a solution.
(iv) 0.2x+0.3y=1.3⇒x=0.21.3−0.3y
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