Solve the following pair of linear equations using substitution method:- 2x + 3y + 5 = 0 ; 5x − 3y + 9 = 0
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Step-by-step explanation:
method 2x+3y=9 , 3x+4y=5
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Answer
We have,
2x+3y=9 ……. (1)
3x+4y=5 …… (2)
Now,
y=
3
9−2x
On putting the value of y, in equation (2), we get
3x+4(
3
9−2x
)=5
3x+
3
36−8x
=5
9x+36−8x=15
x=15−36
Now, put the value of x in equation (1), we get
y=
3
9−2(−21)
y=
3
9+42
y=
3
51
=17
Hence, this is the answer.
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